【修复】修复菜单的路由地址为链接时不带参数的问题
							parent
							
								
									859f25fee3
								
							
						
					
					
						commit
						8f231bc296
					
				| 
						 | 
				
			
			@ -88,7 +88,8 @@ export const generateRoute = (routes: AppCustomRouteRecordRaw[]): AppRouteRecord
 | 
			
		|||
    // 2. 生成 data(AppRouteRecordRaw)
 | 
			
		||||
    // 路由地址转首字母大写驼峰,作为路由名称,适配keepAlive
 | 
			
		||||
    let data: AppRouteRecordRaw = {
 | 
			
		||||
      path: route.path.indexOf('?') > -1 && !route.path.startsWith('http') ? route.path.split('?')[0] : route.path,
 | 
			
		||||
      path:
 | 
			
		||||
        route.path.indexOf('?') > -1 && !isUrl(route.path) ? route.path.split('?')[0] : route.path, // 注意,需要排除 http 这种 url,避免它带 ? 参数被截取掉
 | 
			
		||||
      name:
 | 
			
		||||
        route.componentName && route.componentName.length > 0
 | 
			
		||||
          ? route.componentName
 | 
			
		||||
| 
						 | 
				
			
			
 | 
			
		|||
		Loading…
	
		Reference in New Issue