【修复】修复菜单的路由地址为链接时不带参数的问题
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859f25fee3
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8f231bc296
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@ -88,7 +88,8 @@ export const generateRoute = (routes: AppCustomRouteRecordRaw[]): AppRouteRecord
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// 2. 生成 data(AppRouteRecordRaw)
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// 2. 生成 data(AppRouteRecordRaw)
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// 路由地址转首字母大写驼峰,作为路由名称,适配keepAlive
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// 路由地址转首字母大写驼峰,作为路由名称,适配keepAlive
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let data: AppRouteRecordRaw = {
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let data: AppRouteRecordRaw = {
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path: route.path.indexOf('?') > -1 && !route.path.startsWith('http') ? route.path.split('?')[0] : route.path,
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path:
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route.path.indexOf('?') > -1 && !isUrl(route.path) ? route.path.split('?')[0] : route.path, // 注意,需要排除 http 这种 url,避免它带 ? 参数被截取掉
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name:
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name:
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route.componentName && route.componentName.length > 0
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route.componentName && route.componentName.length > 0
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? route.componentName
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? route.componentName
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