【修复】修复菜单的路由地址为链接时不带参数的问题

pull/556/head
YunaiV 2024-09-17 15:44:09 +08:00
parent 859f25fee3
commit 8f231bc296
1 changed files with 2 additions and 1 deletions

View File

@ -88,7 +88,8 @@ export const generateRoute = (routes: AppCustomRouteRecordRaw[]): AppRouteRecord
// 2. 生成 dataAppRouteRecordRaw
// 路由地址转首字母大写驼峰作为路由名称适配keepAlive
let data: AppRouteRecordRaw = {
path: route.path.indexOf('?') > -1 && !route.path.startsWith('http') ? route.path.split('?')[0] : route.path,
path:
route.path.indexOf('?') > -1 && !isUrl(route.path) ? route.path.split('?')[0] : route.path, // 注意,需要排除 http 这种 url避免它带 ? 参数被截取掉
name:
route.componentName && route.componentName.length > 0
? route.componentName