【修复】修复菜单的路由地址为链接时不带参数的问题
parent
859f25fee3
commit
8f231bc296
|
@ -88,7 +88,8 @@ export const generateRoute = (routes: AppCustomRouteRecordRaw[]): AppRouteRecord
|
|||
// 2. 生成 data(AppRouteRecordRaw)
|
||||
// 路由地址转首字母大写驼峰,作为路由名称,适配keepAlive
|
||||
let data: AppRouteRecordRaw = {
|
||||
path: route.path.indexOf('?') > -1 && !route.path.startsWith('http') ? route.path.split('?')[0] : route.path,
|
||||
path:
|
||||
route.path.indexOf('?') > -1 && !isUrl(route.path) ? route.path.split('?')[0] : route.path, // 注意,需要排除 http 这种 url,避免它带 ? 参数被截取掉
|
||||
name:
|
||||
route.componentName && route.componentName.length > 0
|
||||
? route.componentName
|
||||
|
|
Loading…
Reference in New Issue