修复获得管理员权限时,排序错误的问题
parent
f47e564772
commit
6b6b4d9514
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@ -48,7 +48,9 @@ public class AdminController {
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public CommonResult<List<AdminMenuTreeNodeVO>> menuResourceTree() {
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List<ResourceBO> resources = resourceService.getResourcesByTypeAndRoleIds(ResourceConstants.TYPE_MENU, AdminSecurityContextHolder.getContext().getRoleIds());
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// 创建 AdminMenuTreeNodeVO Map
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Map<Integer, AdminMenuTreeNodeVO> treeNodeMap = resources.stream().collect(Collectors.toMap(ResourceBO::getId, ResourceConvert.INSTANCE::convert));
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// Map<Integer, AdminMenuTreeNodeVO> treeNodeMap = resources.stream().collect(Collectors.toMap(ResourceBO::getId, ResourceConvert.INSTANCE::convert));
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Map<Integer, AdminMenuTreeNodeVO> treeNodeMap = new LinkedHashMap<>(); // 使用 LinkedHashMap 的原因,是为了排序 。实际也可以用 Stream API ,就是太丑了。
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resources.stream().sorted(Comparator.comparing(ResourceBO::getSort)).forEach(resourceBO -> treeNodeMap.put(resourceBO.getId(), ResourceConvert.INSTANCE.convert(resourceBO)));
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// 处理父子关系
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treeNodeMap.values().stream()
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.filter(node -> !node.getPid().equals(ResourceConstants.PID_ROOT))
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@ -64,7 +66,7 @@ public class AdminController {
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// 获得到所有的根节点
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List<AdminMenuTreeNodeVO> rootNodes = treeNodeMap.values().stream()
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.filter(node -> node.getPid().equals(ResourceConstants.PID_ROOT))
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.sorted(Comparator.comparing(AdminMenuTreeNodeVO::getSort))
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// .sorted(Comparator.comparing(AdminMenuTreeNodeVO::getSort))
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.collect(Collectors.toList());
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return CommonResult.success(rootNodes);
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}
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